北京和呼和浩特相距660千米. 一列火车从呼和浩特开出,每时行驶48千米; 另一列火车从北京开出,每时行驶72千米.两列火车同时开出,相向而行,经过几时相遇?两车相遇时,从北京开出的火车比从呼和浩特开出的火车多行了多少千米?

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正确答案:

解:660÷(48+72)

=660÷ 120

=5.5(小时)

答:经过 5.5 小时相遇.

72× 5.5﹣48× 5.5

=396﹣264

=132(千米)

答:两车相遇时,从北京开出的火车比从呼和浩特开出的火车多行了132千米

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