已知某高炉每天下料145批，焦批重14t，f=1.0%，C焦=84.87%，Cφ=75%，1kgC燃料需要的氧量为0.933m3，求每分钟实际入炉风量
解：V＝0.933C焦CφKN/(0.21+0.29f)
＝0.933×0.8487×0.75×14000×145/[(0.21+0.29×0.01)×1440]
＝3932m3/min
答：每分钟实际入炉风量为3932m3/min。
暂无解析
Thereisamixtureofpeoplefromdifferentculturesandethnicgroupsinacountry.Why?Isthisapositiveornegativedevelopment?
Somevisitorsareinterestedinothercountries'culturesandtraditions.Howtheylearnotherculturesandtraditions?Whythisisinterestingtosomevisitorsbutnottoothers?
-----Wouldyoumindmyusingyourpen?
-----_______________.