设数列满足 {an} 满足 a1=0 ，an+1 -2a n=1, 则 a 100 = （）
A
构造等比数列：an+1-2an=1，有an+1=2an+1，令an+1+t=2(2an+t)→an+1=2an+t，所以t=1，所以an+1+1=2(an+1)，所以an+1是以a1+1=1为首项，公比为2的等比数列，所以an=2n-1-1，an=299-1，选A。
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