北京和呼和浩特相距660千米. 一列火车从呼和浩特开出，每时行驶48千米; 另一列火车从北京开出，每时行驶72千米.两列火车同时开出，相向而行，经过几时相遇?两车相遇时，从北京开出的火车比从呼和浩特开出的火车多行了多少千米?
解：660÷(48+72)
=660÷ 120
=5.5(小时)
答：经过 5.5 小时相遇.
72× 5.5﹣48× 5.5
=396﹣264
=132(千米)
答：两车相遇时，从北京开出的火车比从呼和浩特开出的火车多行了132千米
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